Physics, asked by Arshyan7684, 10 months ago

The gravitational potential energy of an isolated system of three particles, each of mass m, at the three corners of an equilateral triangle of side l is

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Answered by Anonymous
38

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Gravitational potential energy of a pair of particles = - \frac{Gm²}{l}

Since we have three pairs, therefore the total gravity potential energy = - \frac{3Gm²}{l}

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