Physics, asked by divyanshunegi953, 7 months ago

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Answers

Answered by VedankMishra
1

Let (A) and (B) be two forces and A>B. Then

A+B14N…(i)

and A-B=4N …(ii) ltBrgt Solving (i) and (ii) , we get

when each force is increased by 2N, then ltbRgt A1=9+2=11N and B1=5+2=7N

Angle between these two forces θ=60∘

Resultant force,

R1=

A-12+B^2+2A1B1cos60∘

=

112+72+2×11×71/2

=

121+49+77

=15.72N ltbRgt Let

R

1 maken an angle β with the force

A

1 , then ltbRgt tanβ=

B1sin60∘

a1+B1cos602

=

3

/2

11+7×1/2

=0.4180 ltbRgt β=22241′.

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