the greatest height to which a man can throw a ball is h what will be the greatest distance upto which he can throw the stone
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The maximum vertical height that the stone achieves =h
Thus the velocity with which the object s thrown upwards v= 2gh
We know range of projectile R= gv 2
sin2θ
=
gv2
Maximum distance can be covered when θ=45 and sin2θ=1
Therefore R= h
2gh=2h
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