Question

The greatest integer function defined by fix) = [x], 0<x<2 is not
differentiable at x =____​

Answer 1

$\rule{300}{2}$

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R:-}}}}$

See this attachment

A graphical representation of [x] is given. By the graph it is clear that greatest integer function is not continuous at integers. Since it is given that 0<x<2, so f(x)=[x] is not continuous at 1, and a point at which function is not continuous then at that point function is not differentiable also.

Hence, f(x) is not differentiable at x=1.

This is the best possible answer

$\large{\boxed{\mathbf\pink{\fcolorbox{cyan}{black}{Hope\:you\:have}}}}$

$\large{\boxed{\mathbf\pink{\fcolorbox{red}{yellow}{Understood}}}}$

$<marquee>♥️Please mark it as♥️</marquee>$

$\huge\underline\mathcal\red{Brainliest}$

$</p><p>\huge{\boxed{\mathbb\green{\fcolorbox{red}{blue}{Thank\:You}}}}$

$\rule{300}{2}$