The sum of three consecutive even number is 54 what would be the smallest of these numbers
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Here is your solution
Let,
The first even integer be:x
Then the second even integer is:x+2
Then the third even integer is: x+2+2=x+4
Sum of three consecutive even numbers =54
A/q
(x)+(x+2)+(x+4)=54
3x+6=54
3x=54-6
3x=48
x=16
now
The first integer is:x=16
the second integer is:x+2=16+2=18
the third integer is: x+4=16+4=20
Hope it helps you
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the first number will be smallest..
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