Question

the greatest number which divides 134 and 167 leaving 2 as remainder in each course is

Answer 1

The largest number which divides 615 and 963 leaving remainder 2 in each case => HCF.

And let the HCF be x.

To make 134 and 167 completely divisible by x we have to sub. 2 from 134 and 167.

134-2=132,167-2=165 

165 = 3*5*11

132= 2*2*3*11

⇒ x =3*11⇒x=33

Therefore the greatest number which divides 134 and 167 leaving 2 as remainder in each case as 33.

            HOPE IT WILL HELP YOU ^_^

Answer 2

Hi mate..The answer is 33 ..I hope it will help you!!