The greatest value of the function-5 sino + 12 cose
(1) 12
(2) 13
(3) 7
(4) 17
Answers
Answered by
3
Answer:
Wait ẞruh
Explanation:
Answer:
The maximum is 13 and minimum is
−
13
.
Explanation:
f
(
t
)
=
5
sin
t
+
12
cos
t
. We can compound these two oscillations into a single sine oscillation.
f
(
t
)
=
13
(
(
5
13
)
sin
t
+
(
12
13
)
cos
t
)
=
13
(
cos
b
sin
t
+
sin
b
cos
t
)
=
13
sin
(
t
+
b
)
, where
sin
b
=
12
13
and
cos
b
=
5
13
.
So,
−
13
≤
f
(
t
)
=
13
sin
(
t
+
b
)
≤
13
The amplitude of the oscillation is 13 and the period is
2
π
IncorrectUsername:
Totally wrong Answer XD
means...........
its a ques of vector how u did add oscillation to it
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