Question

The grid voltage of any triode valve is changed from –1 volt to –3 volt and the mutual conductance is 3 × 10⁻⁴ mho. The change in plate circuit current will be(a) 0.8 mA(b) 0.6 mA(c) 0.4 mA(d) 1 mA

Answer 1

Answer:

B) 0.6mA

Explanation:

Change in the triode valve (vg) = –1 volt to –3 (Given)

Mutual conductance = 3 × 10⁻⁴ mho (Given)

By using the equation of grid voltage = µ  =Δ va/ Δvg

where, µ = amplification factor

ΔVa = change in anode voltage

ΔVg = change in grid voltage

= Δva/ΔvgÞ 3×10−4

= Δva/−1−(−3) Þ Δip

= 6×10−4A

= 0.6 mA

Thus, the change in plate circuit current will be 0.6mA