Question

the ground
A stone dropped from a tree takes 2 second to reach the ground
'Find its velocity on string the ground
Take g = 9.8 m/s²​

Answer 1

Answer:

19.6 m/s

Explanation:

Given data,

t = 2 sec

u = 0 m/s

g = 9.8 m/s^2

v = ?

Using the 2nd equation of motion,

h = ut + 1/2 gt^2

h = 0 x 2 + 1/2 x 9.8 x 2 x 2

h = 1 x 9.8 x 2

h = 19.6 m

Now, we can find 'v' by using the 3rd equation of motion,

2gh = v^2 - u^2

v^2 - u^2 = 2gh

v^2 - 0^2 = 2 x 9.8 x 19.6

v^2 = 384.16

v = √384.16

v = 19.6 m/s

Hope it helps u...

Answer 2

Answer:

velocity on reaching the ground is 19.6m/s

Explanation:

time=2s

u=0 m/s(initially the stone was at rest)

g=9.8m/s²

v=?

a=v-u/t

g=v-u/t

9.8x2=v-0

v=19.6m/s