Question

The ground state energy of h atom is 13.6 electron volt.the energy needed to ionise h atom from its second excited state

Answer 1

Three steps solutions

Explanation:

According to the questions,

we know that,

$E_n = \frac{13.6}{n^2}$   ev

The energy required to ionized atoms from second excited state,

so ,

n = 3

putting the value in above equations,

$E_n = \frac{13.6}{3^2}$

$E_n = \frac{13.6}{9}$

$E_n = 1.5111$  ev