Question

The heat of combustion of butane is 2880 kj/mol. what is the heat liberated by burning 1 kg site:brainly.in

Answer 1

Answer:

Answer should be 49655.1724 KJ

Explanation:

First of all we need to find the total mole of Butene(C2H10).

Molecular Mass of butane is 58 gm/mol.

so for 1000 gm we need 17.24 mol.

we'll multiply the moll with the heat energy for the total mol of butane.

so the answer is 2880 × 17.2413 = 49655.17 KJ