Question

*The ground state energy of hydrogen atom is -13.6 eV. What is the potential energy of the electron in this state?*

1️⃣ 0 eV
2️⃣ -27.2 eV
3️⃣ 1 eV
4️⃣ 2 eV​

Answer 1

Answer:

The total energy of an electron in the first excited state of the hydrogen atom is about -3.4 eV.

Answer 2

Answer:

We know that 2∣P.E∣

=∣T.E∣=K.E

So, 2

∣P.E∣=3.4=K.E

So, kinetic energy K.E=3.4 eV

Potential energy P.E=−2×∣T.E∣=−2×(3.4)=−6.8 eV