Question

The H.C.F of two numbers is 11 and their L.C.M is 7700. If one of the numbers is 275 , then the other is

A) 279 B) 283 C) 308 D) 318

Answer 1

Given :-

• HCF = 11

• LCM = 7700

• One number = 275

To find :-

• The other number = ?

Solution :-

let the other number be x

we know that,

$\small\orange{\bigstar}\:\:{\underline{\boxed{\bf\purple{Product\:of\:HCF\:and\:LCM=Product\:of\:two\:number}}}}$

$\rm\longrightarrow\:11\times\:7700=275\times\:x$

$\rm\longrightarrow\:84700=275x$

$\rm\longrightarrow\:\cancel\dfrac{84700}{275}=x$

$\rm\longrightarrow\:308=x$

$\rm\longrightarrow\:x=308$

Hence,the other number will be 308.

so, option (c) 308 is correct answer

$\blue{\bigstar}\:\:{\underline{\boxed{\bf\red{More\: Information}}}}$

⤇ HCF:-HCF refers to the highest common factor.It is the largest or greatest factor common to any two or more given Natural number.

⤇LCM:-LCM refers to the lowest common multiple.It is the smallest or least common multiple of any two or more given Natural numbers.

Answer 2

Answer:

L.C.M X H.C.F = Product of two numbers

11 X 7700 = 275 X x

11 X 7700/275 = x

x= 308

Step-by-step explanation: