The H.C.F of Two numbers is 12 and their L.C.M is 180. If one of the number is 36. Find the Other
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Given , H.C.F of two numbers = 12
their L.C.M = 180
given,one number = 36
let the other number be ' x '
since , we know that
product of two numbers = H.C.F × L.C.M
36 × x = 12 × 180
solve for ' x ' :
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36x = 2160
x = 60
therefore,other required number is 60
Answer:0ther number = 60
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their L.C.M = 180
given,one number = 36
let the other number be ' x '
since , we know that
product of two numbers = H.C.F × L.C.M
36 × x = 12 × 180
solve for ' x ' :
--------------------
36x = 2160
x = 60
therefore,other required number is 60
Answer:0ther number = 60
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