Question

the H.C.M of the two numbers is 3 and their L.C.M is 54. if one of the number is 27, find the other number.​

Answer 1

Answer:

6

Step-by-step explanation:

LCM*HCF=a*b

54*3=27*b

54*3/27=b

6=b

Answer 2

HCF = 3

LCM = 54.

Num 1 = 27

Let Num 2 = x

LCM × HCF = Num 1 × Num 2

54 ×3 = 27 × x

$\frac{54 \times 3}{27} = x$

$6 = x$

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