The [H3O+] concentration in the 200 ml. H2SO4 solution is 1 M. How much H2so4
is dissolved in the solution ? [H = 1, 0 = 16, S = 32 gram/mole]
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Answered by
24
Answer:
1000 ml.of 1M H2SO4 contains= 98 g
So 200 ml of 1M H2SO4 contains =98/5= 19.6 g.
1 mole of H2SO4 contains= 2 moles of [H3O+] .
So the Solution containing 1M of [H3O+] in 200 ml = 19.6/2
= 9.8g
Explanation:
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Answered by
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Using formula of molarity =no. of mole of solute/
volumeof solution in litre
Molarity =1M
Molar mass of H2SO4=2+32+64=98mol/g
we know that,no.of mole =given mass of solute/vol.of solute
let mass of solute be B
then, no. of mole =B/98
1=B/98×1000/200
B=98×200/1000
=98/5=19.6g
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