Question

The half-life of a redioactive decay is 'x' times its mean life .here is given by​

Answer 1

Answer:

See below.

Explanation:

The mean life of radioactive decay is given by,

$t_{mean} = \frac{1}{\lambda}$

And the half-life is given by,

$t_{1/2} = \frac{\ln 2}{\lambda}$

Comparing both the expressions,

$t_{1/2} = \ln2 \times t_{mean}$

Therefore,

$x = \ln 2 = 2.303 \log( 2 ) = 2.303 \times 0.3 = 0.693$