The half-life of krypton is 10.756 y. Calculate the number of disintegrations per second
of 2.25 g of krypton.
(a) 3.25 x 1010 /
(b) 3.3x1013 /s
(c) 3.61x101° /s
(d) 4.25 x1013 /s
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Answer:
b
Explanation:
t1/2 is 10.756 yrs or 0.339 × 10⁹
number of atoms (N) of kr in 2.25 gm
2.25/83.8× 6.023 × 20²³ = 16 × 10²¹
disintegration per sec
-dN/dt = lambda N = 0.693/ t1/2 × N
0.693/0.339 × 10⁹ × 16 × 10²¹
further solving we get 33 × 10¹²
or 3.3 × 10¹³
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