Question

An ideal gas in a sealed container has an initial volume of 2.60 L. At constant
pressure, it is cooled to 23.00 degrees Celcius, where its final volume is 1.75 L. What
was the initial temperature?
​

Answer 1

Step-by-step explanation:

Answer:-

Given:-

Initial volume of the gas (V₁) = 2.60 L

Final Volume of the gas (V₂) = 1.75 L

Final Temperature (T₂) = 23.00° C = 23 + 273° K = 296° K

[ ∵ °K = °C + 273 ]

We know that,

Charle's law of gases states that at constant pressure, the volume of a gas is directly proportional to its temperature.

That is,

⟹ V ∝ T

⟹ V/T = k (constant)

So,

⟹ V₁/T₁ = V₂/T₂

Let the Initial temperature be T₁.

Hence,

⟹ (2.60)/T₁ = (1.75)/(296)

⟹ (2.60)(296) = T₁ * (1.75)

⟹ (296)(2.60) / 1.75 = T₁

⟹ 439.77° K = T₁

⟹ T₁ = 439.77 - 273°

⟹ T₁ = 166.77° C

∴ The Initial temperature of the gas was 166.77° C.

Answer 2

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