Physics, asked by romeshpasi, 1 year ago

The half life of radon is 3.8 days. In how may days will its activity drop to 6.25% of its initial value?

Answers

Answered by laylamcdow8

4

Answer : (b) 16.5days

Explanation :

Equation for decay of radioactive nuclei will be

N=N0e−λt

Where λln2t12=ln238

N020=N0e−ln2.8t

t=16.5days.

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