Question

The Half Life period of a substance is 50 minutes at a certain initial concentration when concentration is reduced to one half half life is found to 25 minutes order of reaction​

Answer 1

It is given that the half life of the compound is reduced to half (50 mins. to 25 mins.) when initial concentration is reduced to half. This means that half life is directly proportional to initial concentration.

So, the order of the reaction is zero.

Answer 2

Answer : The order of reaction is, Zero order reaction.

Explanation :

Formula used :

$n=\frac{\log(\frac{t_{1/2(1)}}{t_{1/2(2)}})}{\log(\frac{a_2}{a_1})}+1$

where,

n = order of reaction = ?

$t_{1/2}_{1}$ = half-life of a substance at initial concentration = 50 min

$t_{1/2}_{2}$ = half-life of a substance at final concentration = 25 min

$a_{1}$ = initial concentration = X

$a_{2}$ = initial concentration = $\frac{X}{2}$

Now put all the given values in the above formula, we get the order of reaction.

$n=\frac{\log{(\frac{50min}{25min})}}{\log{(\frac{X}{2}}{X})}+1$

$n=0$

Therefore, the order of reaction is, Zero order reaction.