Question

The half life period of first order reaction is 600s.what percentage ofA remains after30 minutes

Answer 1

Answer:

12.5%

Explanation:

t1/2 = 600 sec = 10 min

T = n t1/2

30 = n 10

n = 3

after 1 half life reactant left will be 50%

after 2 half lives reactant left will be 25%

after 3 half lives reactant left will be 12.5%