Question

The handle of a nutcracker is 18 cm long and a nut is placed 2 cm from its hinge. If a force of 36 kgf is placed on the nut,it will crack. Calculate the force which has to be applied at the end of the handle to crack the nut.

Answer 1

We know that,

Distance of nut from fulcrum (d) = 2 cm

Distance of effort from fulcrum (D) = 18 cm

Load × Load arm = Effort × Effort arm

Load × 2 cm = 36 kgf × 18 cm

Load = 324 kgf

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Answer 2

Answer:

The force has to be applied at the end of the handle to crack the nut.

Explanation:

Given:

Nut's distance from the fulcrum (d)= 2 cm

Distance of effort from the fulcrum (D) = 18 cm

To Be Calculated:

The force has to be applied at the end of the handle to crack the nut.

Solution:

We know that,

Nut's distance from the fulcrum (d)= 2 cm

Distance of effort from the fulcrum (D) = 18 cm

We know that

Load × Load arm = Effort × Effort arm

Load × 2 cm = 36 kgf × 18 cm

Load = 324 kgf

Thus, the force has to be applied at the end of the handle to crack the nut.

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