Question

The handle of a nutcracker is 40 cm long and a nut is placed 10 cm from its hinge. If a force of 8 kgf is placed on the nut, it will crack. Calculate the force which has to be applied at the end of the handle to crack the nut.​

Answer 1

Answer:

2 kgf

Explanation:

Load = 8 kgf  

Load arm = 10 cm  

Effort = ?

Effort arm = 40cm  

 

Load x Load arm = Effort x Effort arm  

8kgf x 10 cm = Effort x 40 cm  

 Effort = $\frac{8 * 10}{40}$

Effort = 2 kgf  

 

Thus, to crack the nut the force of 2 kgf must be applied at the end of the handle.