The hcf and lcm of 2 nos. Are 33 and 264 resp. When the first number is completely divided by 2, the quotient is 33. Find the number.
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Heya !!!
The answer of your query is here.
Given :-
HCF = 33.
LCM = 264.
It is also given that if the first number is completely divided by 2, then quotient is 33.
Let the number be x.
According to the question,
x ÷ 2 = 33
x = 33 × 2
x = 66.
So, the first number is 66.
Let the other number be y.
We know that .......
LCM × HCF = PRODUCT OF TWO NUMBERS.
So,
33 × 264 = 66 × y
Hence, the second number is 132.
Hence, the two numbers are 66 and 132.
Hope you got the answer
The answer of your query is here.
Given :-
HCF = 33.
LCM = 264.
It is also given that if the first number is completely divided by 2, then quotient is 33.
Let the number be x.
According to the question,
x ÷ 2 = 33
x = 33 × 2
x = 66.
So, the first number is 66.
Let the other number be y.
We know that .......
LCM × HCF = PRODUCT OF TWO NUMBERS.
So,
33 × 264 = 66 × y
Hence, the second number is 132.
Hence, the two numbers are 66 and 132.
Hope you got the answer
gauri123:
Thanx
Answered by
3
Heya,
It is given that:-
HCF = 33
LCM = 264
1st number is divided by 2
Quotient = 33
Let the first number be "x"
And second number be "y"
=> x/2 = 33
=> x = 33 × 2
=> x = 66
To find the second number,
HCF × LCM = Product of x & y
=> 33 × 264 = 66 × y
=> 33 × 264/66 = y
=> 3 × 264/6 = y
=> 1 × 264/2 = y
=> 264/2 = y
=> 132 = y
Therefore,
First number [x] = 66
Second number [y] = 132
Hope my answer helps you :)
Regards,
Shobana
It is given that:-
HCF = 33
LCM = 264
1st number is divided by 2
Quotient = 33
Let the first number be "x"
And second number be "y"
=> x/2 = 33
=> x = 33 × 2
=> x = 66
To find the second number,
HCF × LCM = Product of x & y
=> 33 × 264 = 66 × y
=> 33 × 264/66 = y
=> 3 × 264/6 = y
=> 1 × 264/2 = y
=> 264/2 = y
=> 132 = y
Therefore,
First number [x] = 66
Second number [y] = 132
Hope my answer helps you :)
Regards,
Shobana
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