Question

the hcf and lcm of 2 numbers are 6a and 360a^2 b^3 respectively. if one of the number is 120b^2, find the other.

Answer 1

Step-by-step explanation:

120b² * x = 360a²b³ * 6a

x = 18a³b

Answer 2

180a^3b

Step-by-step explanation:

Let the other no be 'x'

HCF * LCM = PRODUCT OF YWO NUMBERS

6a * 360a^2 b^3 = 12b^2 * x

6a * 360a^2 b^3 / 12b^2 = x

x = 180a^3 b