Question

The hcf and lcm of a pair of numbers are 11and 1001 .find the smallest of the two numbers given that their sum is 220

Answer 1

Step-by-step explanation:

this is the answer please mark it as brainlist

Answer 2

Answer:

77

Step-by-step explanation:

let the numbers be x , 220 - x ( since sum of 2 numbers = 220)

11 * 1001 = x * (220-x)

x^2 - 220x + 11011 = 0

(x- 143) (x- 77)

x = 143 , 77

hence the numbers are 143,77