Question

The HCF and LCM of a pair of numbers are 12
and 926 respectively. How many such distinct
pairs are possible?
(a) 3 (b) 7
(c) 1 (d) 0

Answer 1

Answer:

O

Step-by-step explanation:

To find number of pairs

First we need to find prime factors, which is LCM/HCF

Since 926 is non divisible by 12, hence it doesn't have any factors.

Example -

If we take number 924 then

924/12 = 77

77 = 11*7

Hence, for 924 it will have two pairs.

Answer 2

Answer:

Total number of possible pairs is 2 , (77,1) and (11 ,7)

Step-by-step explanation:

Explanation:

Given ,  HCF and LCM of a pair of numbers are 12 and 962 .

Let  two numbers be 12x and 12 y .

 LCM of these two number = 12× x× y  = 12xy

But given in the question that LCM of a pair of numbers are  926 .

Step 1:

According to the given information we have ,

12 xy = 926

⇒ xy = $\frac{926}{12}$ = 77.1 = 77

Therefore , product of xy = 77 .

So, the number of pairs are (77,1 ) and (7 , 11) .

Final answer:

Hence , there are two possible pair .

#SPJ3