Question

the hcf and lcm of p(x) and q (x) are (2x-1) and (6x cube + 25x square - 24x + 5) respectively. If p(x)= 2x square + 9x -5, determine q(x)

Answer 1

Answer:

6x^2-5x+1

Step-by-step explanation:

We know. Hcf×Lcm=product of two numbers

so (2x^2+9x-5)(q(x)=(2x-1)(6x^3+25x^2-24x+5)

here 2x^2+9x-5=(2x-1)(x+5)

so

(2x-1)(x+5)(q(x)=(2x-1)(6x^3+25x^2-24x+5)

6x^3+25x^2-24x+5=(6x^2-5x+1)(x+5)

so q(x)=6x^2-5x+1