Question

The HCF and LCM of two number is 19 and 114.if one of the number is 38 then the other number is what.​

Answer 1

Answer:-

• HCF = 19
• LCM = 114

• One number is 38

we have to calculate the another number

Let the another number be n.

As we know that ,

• Product of HCF & LCM = Product of Two Number

Substitute the value we get

$:\implies$ HCF × LCM = 38 × n

$:\implies$ 19×114 = 38×n

$:\implies$ 2166 = 38 × n

$:\implies$ 38×n = 2166

$:\implies$ n = 2166/38

$:\implies$ n = 57

• Hence, the another number is 57 .

Answer 2

Given that , The HCF and LCM of two number are 19 and 114 , respectively & one of the number is 38 .

Need To Find : The other number ?

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

❍ Let's say that another number be x .

As , We know that ,

$\qquad \star \:\:\underline {\boxed{ \pink{\pmb{\bf{ \:Product \:of \:two \:numbers\:=\:\:H.C.F \:\:\times \:L.C.M \:\: \:}}}}}$

⠀⠀⠀⠀⠀Where ,

• H.C.F ( or Highest Common Factor ) is 19 ,
• L.C.M ( or Lowest Common Factor ) is 114 &
• One of the number is 38 .

$\qquad \dashrightarrow \sf \:\:H.C.F \:\:\times \:L.C.M \:\:=\:\:First \:\:Number\:\:\times Other \:Number$

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}$

$\qquad \dashrightarrow \sf \:\:H.C.F \:\:\times \:L.C.M \:\:=\:\:First \:\:Number\:\:\times Other \:Number \\\\\qquad \dashrightarrow \sf \:\:19 \:\:\times \:114 \:\:=\:\:38\:\:\times x \\\\\qquad \dashrightarrow \sf \:\:2166 \:\:=\:\:38\:\:\times x \\\\\qquad \dashrightarrow \sf \:\:\dfrac{2166}{28} \:\:=\:\: x \\\\\qquad \dashrightarrow \sf \:\:\cancel {\dfrac{2166}{28}} \:\:=\:\: x \\\\\qquad \dashrightarrow \sf \:\:57 \:\:=\:\: x \\\\\qquad \dashrightarrow \sf \:\:x \:\:=\:\: 57 \\\\\qquad \therefore \:\: \underline{\boxed{\purple {\pmb {\frak{ \:\: x\:\:(\:or \:Other \:number\:)\:=\: 57 \:\:}}}}}$

Therefore,

• Other number is x = 57

$\qquad \therefore \:\:\underline {\sf \: Hence, \:The \:other \:number \: is \: \bf 57 \:}$