Math, asked by aqsakhan878878, 1 year ago

The HCF and LCM of two numbers are 12 and 2448 respectively. If the difference of the numbers is 60, then what is the sum of the numbers is:

A) 284

B) 248

C) 204

D) 348

Answers

Answered by varsha4499
0

Answer:

348

Step-by-step explanation:

let one no. be X

other be y

ATQ

x-y=60

X=60+y

HCF×LCM=xy

12×2448=29376

xy=29379

(60+y)y=29379

y^2+60y-2937=0

by quadratic formula

D=b^2-4ac

60^2-4×1×(-29379)

3600+117516

121116

D=121116

X=-b+-✓121116/2

-60+-348.017

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