The HCF and LCM of two numbers are 12 and 2448 respectively. If the difference of the numbers is 60, then what is the sum of the numbers is:
A) 284
B) 248
C) 204
D) 348
Answers
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0
Answer:
348
Step-by-step explanation:
let one no. be X
other be y
ATQ
x-y=60
X=60+y
HCF×LCM=xy
12×2448=29376
xy=29379
(60+y)y=29379
y^2+60y-2937=0
by quadratic formula
D=b^2-4ac
60^2-4×1×(-29379)
3600+117516
121116
D=121116
X=-b+-✓121116/2
-60+-348.017
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