the hcf and lcm of two numbers are 8 and 1728 respectively accordingly how many pairs of such digits are there
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HCF * LCM = 1st number * 2nd Number. For HCF 8, one shall be 8
8 * 1728 = 8 * 2*2*2*2*2*2*3*3*3 = 8 * 8 *2*2*2*3*3*3
Non the number will be less than 8, thus -
8 & 1728 is the 1st option & the 2nd option is 64 & 216
thus, there is only two pairs.
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