Question

the hcf and lcm of two positive integers are h and l respectively. if one integer is a find the other integer.

Answer 1

we know very well that ____

product of two number =HCF × LCM
a × b = h × l
therefore, b =hl/a ANS_______

Answer 2

The hcf and lcm of two positive integers are "h" and "l" respectively. if one integer is "a" then the other integer is $\frac{h \times l}{a}$

Solution:

Let the other integer be “y"

One of the integer is given as "a"

The relation between H.C.F and L.C.M is given as:

For two positive integers a, b:

$\text { H. C . F} \times L . C . M=a \times b$

H.C.F (of two intergers a and y) x L. C.M (of two integers a and y) = a x y

Here, H.C.F is Highest common factor and L.C.M is Lowest Common Multiple

[ Since it is given that H.C.F is h and L.C.M is l]

$\begin{array}{l}{h \times l =a \times y} \\\\ {\frac{h \times l}{a}=y}\end{array}$

So the integer is $\frac{h \times l}{a}$

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