Question

The hcf lcmof two numbers is 15 and 420 respectively. if one of the number is 60 find the other number

Answer 1

we know that
product of the no. = l.c.m×h.c.f
so. second no. =15×420/60=105.

Answer 2

We know,


HCF × LCM = product of numbers

$= > 15 \times 420 = 60 \times other \: number \\ \\ = > \frac{15 \times 420}{60} = other \: number \\ \\ = >15\times 7 = other \: number \\ \\ = > 105 \: = other \: number$