Math, asked by kundralrsk1174, 12 hours ago

the hcf of 0.02, 0.4, 0.008 is...?​

Answers

Answered by sweetymondal89
2

Answer:

0.004

Step-by-step explanation:

Make all the numbers 0.02, 0.4, and .008 as whole numbers by multiplying all the numbers with 1000

Therefore the numbers will become; 20, 400 and 8

Now find the prime factors of the numbers; 20, 400 and 8

Prime factorization of 20: 2×2× 5

Prime factorization of 400: 2 × 2 × 2 × 2 × 5 × 5

Prime factorization of 8: 2 × 2 × 2

Now the common factors among all the prime factors of 20, 400and 8 are: 2×2

The HCF of 20, 400 and 8 is 2× 2= 4

Now the required H.C.F. of 0.02, 0.4 and 0.008is: 4/1000 = 0.004

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