Question

The HCF of 150 and k is 30. The value of k can be equal to

Answer 1

Answer:

I think there are options for the question.

Step-by-step explanation:

ok so try taking out the HCF of all the 4 options .

and we got k = 210.

primefactorisation of 210 and 150.

150=2×3×5×5

210=2×3×5×7.

now we found that the value of k is 210.

actually if 210 is there in the option then its absolutely correct. just believe me!!!

thank u .

hope u r satisfied with the answer.

Answer 2

Given,

HCF of 150 and $k$ is 30.

So, the prime factorization of 150 would be,

150 = 2 × 3 × 5 × 5

Now, we have to find the number $k$ for which the HCF would be 30.
So, the prime factorization of k would be,

$k$ = 2 × 3 × 5

From here we get k = 30, so numbers will be 150 and 30.

But, we can also get another pair of numbers whose HCF would be 30,

$k$ = 2 × 2 × 2 × 3 × 5

From here we get  $k$ = 120, so numbers will be 150 and 120.

Now we can also get,

$k$ = 2 × 3 × 5 × 7

From here we get  $k$ = 210, so numbers will be 150 and 210.

Then,

$k$ = 2 × 2 × 3 × 5
From here we get  $k$ = 60, so numbers will be 150 and 60.

Hence,  the possible value of $k$ for which the HCF of 150 and $k$ is 30 would be 30, 120, 210, 60.

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