Question

The HCF of 2/3, 8/9, 64/81 and 10/27 is

Answer 1

Answer:

Step-by-step explanation:

2/3 = 2/3

8/9 = (2/3)×(4/3)

64/81 = (2/3)×(32/27)

10/27 = (2/3)×(5/9)

hcf(2/3, 8/9, 64/81, 10/27) = 2/3.

Answer 2

$\text{HCF}(\frac{2}{3}, \frac{8}{9}, \frac{64}{81},\frac{10}{27})=\frac{2}{81}$

Step-by-step explanation:

Given : Fractions $\frac{2}{3}, \frac{8}{9}, \frac{64}{81},\frac{10}{27}$

To find : The HCF of fraction ?

Solution :

The highest common factor of fractions is given by,

$\text{HCF of a Fraction}=\frac{\text{HCF of the numerators of the fractions}}{\text{LCM of the Denominators of the Fractions}}$

HCF of the numerator 2,8,64,10

Factors of the number is

$2=2\times 1$

$8=2\times2\times 2$

$64=2\times2\times2\times 2\times 2\times 2$

$10=2\times 5$

$HCF(2,8,64,10)=2$

LCM of the denominator 3,9,81,27

3 | 3  9  81  27

3 | 1   3  27  9

3 | 1   1   9   3

3 | 1   1   3   1

  | 1   1   1   1

$LCM(3,9,81,27)=3\times3\times 3\times 3=81$

So, HCF of $\frac{2}{3}, \frac{8}{9}, \frac{64}{81},\frac{10}{27}$

$\text{HCF}(\frac{2}{3}, \frac{8}{9}, \frac{64}{81},\frac{10}{27})=\frac{2}{81}$

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HCF of 2/3,8/9,64/81,10/27 is

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