Question

The HCF of 2(x²-y²) and 5(x³-y³) is...??

Answer 1

Solution :

Find the factors of two expressions:

2( x² - y² ) = 2(x+y)(x-y)

5(x³-y³) = 5( x - y )( x² + xy + y² )

Required HCF = ( x - y )

••••

Answer 2

Heyyyy mate..


here is your answer...

given,

2 ( x^²-y^²)>>>>> (X+y)(x-y)

5(x^³-y^³)>>>>>> ( x-y) ( x^²+xy+y^²)

so required HCF = (x-y)

hope it help you