Question

the hcf of 210 and 55 is expressible in the form 210*5-55x,find x

Answer 1

First find the hcf of 210 and 55 using Euclid division lemma,
210=55(3)+45
55=45(1)+10
45=10(4)+5
10=5(2)+0

Hcf is 5
It is expressed in form of 210×5-55x
5=210(5)-55x
5=1050-55x
55x=1050-5
55x=1045
x=1045/55
x=19

Hope it helps