The hcf of 2472, 1284 and a third number â€n’ is 12. If their lcm is 23 Ă— 32 Ă— 51 Ă— 103 Ă— 107, then the number â€n’ is:
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2^2 × 3^2 × 5 because
LCM(2472,1284,N)=23×32×5×103×107LCM(2472,1284,N)=23×32×5×103×107
2472=23∗3∗1032472=23∗3∗103
1284=22∗3∗1071284=22∗3∗107
In order to produce required LCM our N should have 3^2 and 5this is your answer i think it may help you
LCM(2472,1284,N)=23×32×5×103×107LCM(2472,1284,N)=23×32×5×103×107
2472=23∗3∗1032472=23∗3∗103
1284=22∗3∗1071284=22∗3∗107
In order to produce required LCM our N should have 3^2 and 5this is your answer i think it may help you
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