Question

The HCF of 3z, 12zx and 42xy is

Answer 1

$\huge\fbox \red{A}\fbox \green{N}\fbox \purple{S}\fbox \orange{W}\fbox \red{E}\fbox \blue{R}$

3z,12zx,42xy → 3x(z+4z+14y) → HCF = 3x.

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Answer 2

Answer:

3X

Step-by-step explanation:

3z,12zx,42xy → 3x(z+4z+14y)