Question

The HCF of 65 and 117 is expressible in the form 65 m - 117 the value of M is

Answer 1

Answer:

Let us find the HCF of 65 and 117,

117 = 1 × 65 + 52

65 = 1 × 52 + 13

52 = 4 ×13 + 0

therefore HCF of 65 and 117 is 13.

65m -117 = 13

65m = 117+13 = 130

m =130 / 65 =2