Question

The hcf of the numbers of the form 2m and 3n?

Answer 1

Answer:

It will be 1. As both 2 and 3 are prime numbers so both of them will always have factors of there own powers.

Example : Factors of 2^6 will be (2^0, 2^1,2^2,…,2^6).

Factors of 3^4 will be (3^0,3^1,….,3^4).

Therefore due to this no value of 2^m is divisible by 3 and vice versa.

Hope it helps you ｡◕‿◕｡

Please mark my answer brainliest (◠‿◕)

Answer 2

Answer:

they have there own factors and powers