Question

The HCF of two number 29 and its LCM is 4147 then find the number ?
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Answer 1

Answer:

696 As the HCF of the two numbers is 29, they are the multiple of 29. Let the numbers are 29x and 29y

Step-by-step explanation:

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Answer 2

Answer:

the numbers are 11 and 13

Step-by-step explanation:

The HCF is 29

So, let the numbers be 29x and 29y

We know that,

product of numbers=HCF×LCM

29x × 29y= 29×4147

divide this equation by 29

so,. xy=1×143

xy=143

so, the only prime factors of 143 are 11 and 13 or 13 or 11

so, x=11 or 13

y = 11 or 13

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