Math, asked by sonamoniroy98884, 10 months ago

The HCF of two number is 23 and their LCM is 1449. If one number is 161, the other number is

Answers

Answered by Mihir1001

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$Answer:$

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$\huge\boxed{\fcolorbox{red}{#ffdfff}{207}}$

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$Step-by-step-explaination:$

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let the other number be x.

therefore,

A/Q, H.C.F(x,161) = 23

and, L.C.M(x,161) = 1449

Now,

we know that :

$HCF(a,b) \times LCM(a,b) = a \times b$

Hence,

$23 \times 1449 = 161 \times x$

$\implies x = \frac{23 \times 1449}{161}$

$\implies x = \frac{23 \times 207 \times 7}{23 \times 7}$

$\implies x = \frac{1 \times 207 \times 1}{1 \times 1}$

$\implies x = 207$

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