Math, asked by sonamoniroy98884, 8 months ago

The HCF of two number is 23 and their LCM is 1449. If one number is 161, the other number is ​

Answers

Answered by Mihir1001
38

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<font color="blue" size="5px"><b>Answer:</b></font>

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\huge\boxed{\fcolorbox{red}{#ffdfff}{207}}

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<font color="red" size="5px"><b>Step-by-step-explaination:</b></font>

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let the other number be x.

therefore,

A/Q, H.C.F(x,161) = 23

and, L.C.M(x,161) = 1449

Now,

we know that :

HCF(a,b)  \times LCM(a,b) = a \times b

Hence,

23 \times 1449 = 161 \times x

 \implies x =  \frac{23 \times 1449}{161}

 \implies x =  \frac{23 \times 207 \times 7}{23 \times 7}

 \implies x =  \frac{1 \times 207 \times 1}{1 \times 1}

 \implies x = 207

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Answered by KhataranakhKhiladi2
10

SHORT WAY :-

as we know,

HCF * LCM = product of numbers

23*1449 = 161*x ( let the other no. be x )

23*1449/161=x

207 = x

hence, the other no. is 207

LONG WAY:-

let a&b be two numbers

so,Lcm of a&b= 1449

and HCF of a&b =23

and let one number be a so, a=161

according to formula H=axb/L

23=161xb/1449

1449x23/161=b

therefore b=207

so, another number is 207.

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