Math, asked by agbley284, 10 months ago

The HCF of two numbers is 11 , and their LCM is 368. If one number is 64 , then the other number is ... What

Answers

Answered by Rishabh2180
0

Answer:

we know that product of numbers = hcf *lcm

let the number to be found be a

64*a = 368*11

a = 368*11/64

I am leaving the calculation part on you

Answered by amitnrw
0

mistake in data that HCF of two numbers is 11 , and their LCM is 368. If one number is 64

Step-by-step explanation:

The HCF of two numbers is 11 , and their LCM is 368

if HCF of two numbers  is 11

then two numbers should be  11a  & 11b  where a , b  are +ve integers

but 11 is not factor of 64

Hence their is mistake in data

Then using formula  

LCM * HCF = number 1 * number 2

=> 368 * 11  = 64  *  number 2

=>  number2 = 63.25  not an integer

hence mistake in data

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