The HCF of two numbers is 11 , and their LCM is 368. If one number is 64 , then the other number is ... What
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Answer:
we know that product of numbers = hcf *lcm
let the number to be found be a
64*a = 368*11
a = 368*11/64
I am leaving the calculation part on you
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mistake in data that HCF of two numbers is 11 , and their LCM is 368. If one number is 64
Step-by-step explanation:
The HCF of two numbers is 11 , and their LCM is 368
if HCF of two numbers is 11
then two numbers should be 11a & 11b where a , b are +ve integers
but 11 is not factor of 64
Hence their is mistake in data
Then using formula
LCM * HCF = number 1 * number 2
=> 368 * 11 = 64 * number 2
=> number2 = 63.25 not an integer
hence mistake in data
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