Question

the HCF of two numbers is 145 and their LCM is 2175 one of the numbers is 725 find the other number

Answer 1

Answer:

$other \: number \: = \frac{lcm \times hcf}{first \: number} \\ = \frac{2175 \times 145}{725} \\ = 3 \times 145 \\ = 435$

Answer 2

Step-by-step explanation:

let the 1st number=a[a=725] & other number = "b".

give :-)HCF(725,b)=145

LCM(725,b)=2175

1st number is=725

we know that [a×b=HCF (a,b)×LCM(a,b)]

now by using this formula we get,

725×b=145×2175

b=145×2175/725

b=315,375/725

b=435

Hence the other number is 435.