Question

The HCF of two numbers is 23 and their LCM is 1449. If one of the numbers is 161, then the​

Answer 1

Answer:

207

Step-by-step explanation:

we know that HCFxLCM=product of the two numbers

here hcf=23 and lcm=1449

1st number=161 2nd number=?

let the 2nd number be A then,

hcfxlcm=product of two numbers

23x1449= 161x A

23x1449/161= A

207= A

hope this helps

Answer 2

$\huge \rm \underline \red{Answer}$

One number × another number = HCF × LCM

a × b = HCF × LCM

161 × b = 23 × 1449

161 × b = 33327

$b = \frac{33327}{161}$

$\large \boxed{b = 207}$