Question

the hcf of two numbers is 273 and lcm is 3003. if first number is 7, find the second number.​

Answer 1

Answer:

$25xy {2 {242 { {y}^{2} }^{2} }^{?} }^{2} \times \frac{?}{?}$

man of srep and step

Answer 2

Answer:

Let the first number (a) be 273 and the second number be b. It is given that HCF (a, b) = 7 and LCM (a, b) = 3003. We know that HCF LCM = Product of two numbers. Hence, the other number is 77.