The HCF of two numbers is 9 and their
LCM is 585. If one of the numbers is 45.
Find the other
(a) 117
(c) 105
(b) 120
(d) none
Answers
Answered by
0
Answer:
good evening... have a great day
Answered by
0
Answer:
a
Step-by-step explanation:
Let the other number be x
HCF×LCM = Product of two numbers
9×585 = 45× x
5265 ÷ 45 = x
117 = x
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